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Bunuel
How many kilograms of a 15% salt solution must be added to 5 kilograms of a solution that is 8% salt so that the resulting solution is 10% salt?

A. 1
B. 1.5
C. 2
D. 2.5
E. 3

Veritas Prep Official Explanation



Create a starting equation that accounts for the current conditions: (.4 Kilograms Salt)/(5 Kilograms Total) = 8%. Since you are now adding 15% salt solution instead of pure salt, you must put all of what you add in the denominator but only the salt portion in the numerator: (.4 + .15x)/(5 + x) = 1/10. Cross-multiply to get 4 + 1.5x = 5 + x, so .5x = 1 and x = 2.
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meanup
Using allegation and mixture

meanup why are you multiplying by 1 ?
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meanup
Using allegation and mixture

why are you multiplying by 1 ?

Given, 5 kilograms of a solution that is 8% salt. Therefore we are substituting the value 5 kg for the 8% solution here. \(\frac{5}{5}=1\) We are now multiplying 1 with the second solution i.e. 15% salt first solution.
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meanup
Using allegation and mixture
can you please explain what you mean in this picture?
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meanup
Using allegation and mixture
can you please explain what you mean in this picture?

Here is a better explanation for the above question. Let me know if you need any clarification.
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[/quote]

Let y be the solution to be added to the 5kg that is 8% salt.

then :
8%(5kg)+15%(y) = 10%(5kg+y)

==>0.4kg+0.15y=0.1(5kg+y)

0.4kg+0.15y=0.5kg+0.1y

0.05y=0.1kg.

==>y=(0.1kg/0.05)=2kg

Ans.C
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