meanup
\(\frac{5*10*21.25}{80}=\frac{4*30*76.50}{x}\)
\(x= 120\)
meanup the equation you have created does not solve for the number of lamps recquired and will not result in \(x=120\).
By multiplying the hours by the days by the price, and then dividing it by the number of lamps you are working out what the price is for a single lamp which stays on for that specific time frame. To make this method work you need to set them to both work for the same amount of time:
80 lamps, lit 5 hours per day for 10 days for $21.25:
Lamps = 80, hours worked = 50, cost = 21.25 (1)x number of lamps, lit for 4 hours per day for 30 days, for $76.50:
Lamps = x, hours worked = 120, cost 76.5 (2)The LCM time would be 600:
(1) Lamps = 80, hours worked = 50*12, cost= 21.25*12
(2) Lamps = x, hours worked = 120*5, cost= 76.5*12Now one can use the same equation as you did above [ie. (time*price)/lamps]: \(\frac{(50*12*21.25*12)}{80}=\frac{(120*5*76.5*5)}{x}\)
Solving for x will result in 120, but it muddies things.
The easiest way would be to solve for the number of lamps required is to set up the equation to be for price per hour worked. As an equation that would be: (cost)/(number of lamps*hours)
\(\frac{21.25}{80*50} = \frac{76.5}{120*x}\)
\(21.25x = \frac{76.5*50*80}{120}\)
Multiply through by 4\(85x = \frac{76.5*50*80}{30}\)
\(x = \frac{(76.5*80)}{51}\)
\(x = 1.5*80\)
\(x = 120\)
ANSWER B