Pigna351
BrentGMATPrepNow
Bunuel
From the integers from 2 to 40 inclusive, one integer is selected at random. What is the probability that it is a perfect square or a multiple of 9 ?
A. 17/39
B. 4/13
C. 3/13
D. 5/39
E. 4/39
P(selected integer is a perfect square or a multiple of 9) = (number of integers that are perfect squares or multiples of 9)/(total number of integers from 2 to 40 inclusive)
Number of integers from x to y inclusive equals y - x + 1So, the number of integers from 2 to 40 inclusive = 40 - 2 + 1 =
39At this point it's probably easiest to just list all integers that are perfect squares or multiples of 9.
Perfect squares: 4,
9, 16, 25,
36 (
5 integers)
Multiples of 9:
9, 18, 27,
36 (
2 integers, since we don't want to count
9 and
36 twice)
So, there are
7 integers that are perfect squares or multiples of 9:
P(selected integer is a perfect square or a multiple of 9) =
7/
39Answer:????
Sorry for the question, but if it is asked the probability of a number which is a perfect square OR a multiple of 9 then the numbers 9 and 36 belong to both categories so they are not perfect square OR multiples of nine. Wouldn't better to consider only 4,16,25,18 and 27? Hence the answer will be 5/39.
No need to apologize! Actually, "or" in probability means either condition can be true, and it
does include cases where both conditions overlap.
So, when asked for the probability that a number is a perfect square or a multiple of 9, we need to count all integers that meet
either condition. Numbers like 9 and 36, which meet both conditions, are still counted but only once to avoid double-counting. Therefore, the correct answer includes 4, 9, 16, 25, 36, 18, and 27, giving 7 numbers in total.
So the probability is 7/39.