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The number of permutations of n things in a circle, when clockwise and anti clockwise are considered to be different is = (n - 1)!

Let us consider the 3 women as 1 unit. So we have 6 units (5 boys + 1 unit of 3 women) to arrange.

External arrangement = (6 - 1)! = 5! = 120

Internal arrangement of the women = 3! = 6

Total number of ways = 120 * 6 = 720


Option B

Arun Kumar



If I am wrong please explain. Thank you.

My Calculation:

Suppose 3 women as 1. The total becomes 6 people(5 boys + 1):

Based on 6 people, the total arrangement possible = 6! = 720

Now, Internal arrangement of the women = 3! = 6

Total number of ways = 720 * 6 = 4320, therefore, my answer is E.



hi anonymous19...we have to arrange them in a circle. so the 6 units have to be arranged as (6 - 1)! = 5! = 120

Hope this helps

Arun Kumar
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In how many ways can 5 boys and 3 women be arranged in a circle if the women are always to stand together ? (2 seating arrangements are considered different only when the positions of the people are different relative to each other.)

A. 120
B. 720
C. 1080
D. 1440
E. 4320
Solution:

Recall that the number of arrangements of n objects in a circular fashion is (n - 1)!. So if there are no restrictions, the 8 people can be seated in (8 - 1)! = 7! different ways. However, since the three women have to sit together, they can be considered as 1 “entity” person. In other words, we can treat the situation as if there are only 6 people (the 1 “entity” person and the 5 boys), and hence there are (6 - 1)! = 5! seating arrangements. However, since the three women can be seated in 3! ways, there are a total of 5! x 3! = 120 x 6 = 720 different seating arrangements.

Answer: B
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