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Asked: If a^5 ≤ a, which of the following must be true?

a^5 - a <=0
a(a^4-1) <=0
a(a-1)(a+1)(a^2+1) <=0
Since (a^2 + 1) > 0
Using wavy line method,
a<=-1 or 0<=a<=1

I. –1 ≤ a ≤ 0: CAN NOT BE TRUE
II. a = 0; MAY BE TRUE
III. 0 ≤ a ≤ 1; MAY BE TRUE

A. None of the above
B. I only
C. II only
D. III only
E. I and III only

IMO A
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Can someone please explain why II is wrong ?

Bunuel
If a^5 ≤ a, which of the following must be true?

I. –1 ≤ a ≤ 0
II. a = 0
III. 0 ≤ a ≤ 1

A. None of the above
B. I only
C. II only
D. III only
E. I and III only
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Can someone please explain why II is wrong ?

Bunuel
If a^5 ≤ a, which of the following must be true?

I. –1 ≤ a ≤ 0
II. a = 0
III. 0 ≤ a ≤ 1

A. None of the above
B. I only
C. II only
D. III only
E. I and III only

The question asks which of the following MUST be true, not which COULD be true. II is wrong because a = 0 is just one possible case; the inequality holds for other values too, so it’s not always true.
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Bunuel Krunaal how to deal with these kind of questions?
I often mess up with these kind of questions (for instance, here, I was confused like, either II or III seems feasible, if there was a option Both II and III , I would have probably chosen that as my option for this quesiton)
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Nikkz99
Bunuel Krunaal how to deal with these kind of questions?
I often mess up with these kind of questions (for instance, here, I was confused like, either II or III seems feasible, if there was a option Both II and III , I would have probably chosen that as my option for this quesiton)
When asked to check if something must be true, one strategy you can follow is to find a case which doesn't adhere to the statement that must be true but still satisfies the criteria.

For example,

\(a^5 ≤ a = a^5 - a ≤ 0\)

=> \(a*(a^4 - 1) ≤ 0\)

From here we know that a ≤ -1 or 0 ≤ a ≤ 1

Now we are asked which of the below statements must be true,

I. -1 ≤ a ≤ 0

a can be -1, so this statement can be true, but a can also be something from 0 to 1, in which case this statement necessarily need not be true. So it's not necessary that this statement must be true.

II. a = 0

a can be 0, so a = 0 can be true, but a can also be something less or equal to than -1, in which case this statement necessarily need not be true. So it's not necessary that this statement must be true.

III. 0 ≤ a ≤ 1

Again, while a can be something from 0 to 1, but it can also be something less than equal to -1, so this statement necessarily need not be true.

If you observed above, we tried to find a case that proves that the statement while can be true, but must necessarily need not be true.

If there was an option both II and III then you would've asked yourself that a can also be less than or equal to -1.

Hope it helps.
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