Nikkz99
Bunuel Krunaal how to deal with these kind of questions?
I often mess up with these kind of questions (for instance, here, I was confused like, either II or III seems feasible, if there was a option Both II and III , I would have probably chosen that as my option for this quesiton)
When asked to check if something
must be true, one strategy you can follow is to
find a case which doesn't adhere to the statement that must be true but still satisfies the criteria.For example,
\(a^5 ≤ a = a^5 - a ≤ 0\)
=> \(a*(a^4 - 1) ≤ 0\)
From here we know that
a ≤ -1 or
0 ≤ a ≤ 1Now we are asked which of the below statements
must be true,
I. -1 ≤ a ≤ 0
a can be -1, so this statement
can be true, but
a can also be something from 0 to 1, in which case
this statement necessarily need not be true. So it's
not necessary that this statement
must be true.
II. a = 0
a can be 0, so a = 0
can be true, but
a can also be something less or equal to than -1, in which case
this statement necessarily need not be true. So it's
not necessary that this statement
must be true.
III. 0 ≤ a ≤ 1
Again, while
a can be something from 0 to 1, but it
can also be something less than equal to -1, so
this statement necessarily need not be true.
If you observed above, we tried to find a case that proves that the statement while
can be true,
but must necessarily need not be true.If there was an option both II and III then you would've asked yourself that
a can also be less than or equal to -1.
Hope it helps.