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![[(n+3)!]^5/[(n+2)!]^5 =](/forum/styles/gmatclub_light/imageset/icon_post_target_unread.svg "[(n+3)!]^5/[(n+2)!]^5 ="){kind=icon}
29 Apr 2021, 09:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
87% (00:54) correct
13%
(01:23)
wrong
based on 199
sessions
History
Date
Time
Result
Not Attempted Yet
\(\frac{[(n+3)!]^5}{[(n+2)!]^5} =\)
A. 2
B. (n+1)^5
C. (n+2)^5
D. (n+3)^5
E. ((n+3/(n+2))^5
A. 2
B. (n+1)^5
C. (n+2)^5
D. (n+3)^5
E. ((n+3/(n+2))^5
29 Apr 2021, 10:08
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[[(n+3)(n+2)!]^5]/[(n+2)!]^5= (n+3)^5
Hence D.
Hence D.
29 Apr 2021, 12:35
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Bunuel
\(\frac{(n+3)!^{5}}{(n+2)!^5}\) = \(\frac{(n+2)!^{5}(n+3)^{5}}{(n+2)!^{5}}\) = \((n+3)^{5}\)
