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07 May 2021, 19:15
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D
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Difficulty:
35%
(medium)
Question Stats:
77% (02:43) correct
23%
(02:49)
wrong
based on 157
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Five times a number is 22 more than 4 times another number. If the sum of three times the bigger number and 7 times the smaller number is 32, what is the smaller number?
(A) 5
(B) 4
(C) 3
(D) 2
(E) 1
Posted from my mobile device
(A) 5
(B) 4
(C) 3
(D) 2
(E) 1
Posted from my mobile device
07 May 2021, 19:34
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Let one number is x and the other is y.
So,\( 5x = 22 + 4y\) (equation 1).
Now which one is bigger x or y?
If x is bigger, then equation will be \(3x+7y=32\)
but, if y is bigger then equation will be \(3y+7x=32\).
I am confused about it, can you please explain?
If we count x as bigger number only then we get an integer value of smaller number y.
That is 2.
So, answer is D
Posted from my mobile device
So,\( 5x = 22 + 4y\) (equation 1).
Now which one is bigger x or y?
If x is bigger, then equation will be \(3x+7y=32\)
but, if y is bigger then equation will be \(3y+7x=32\).
I am confused about it, can you please explain?
If we count x as bigger number only then we get an integer value of smaller number y.
That is 2.
So, answer is D
Posted from my mobile device
07 May 2021, 20:56
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Emdad
Let one number be x and other number be y.
Given: 5x = 4y + 22. Sum of 3 times the bigger number and 7 times the smaller number is 32.
Smaller number =?
From data:
5x = 4y + 22 ...i
Case 1:
x is the bigger number, y is the smaller number.
3x + 7y = 32 ...ii
Solving equation i and ii, we get:
x = 6 and y = 2
Smaller number is 2.
Case 2:
x is the smaller number, y is the bigger number
3y + 7x = 32 ...iii
Solving equations i and iii, we get:
x \(\approx\) 4.51 and y \(\approx\) 0.139
Here, we can see that y = 0.139 is a smaller number, but it contradicts with our Case statement that "y is the bigger number".
So, this case is not possible.
From case 1, smaller number is 2 only.
So, correct answer is option D.
