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Bunuel
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Use the formula D=RT.
D1=R1T
D2=R2T
Everytime they meet at the starting point, P2 will have covered x times 1200 m more that P1 (ex: first time they meet x=1, second time they meet, x=2).
So D2=D1+(1200*x).
Since we want to know the first time they meet, x=1 and D2=D1+1200
R2T=R1T+1200, solve for T. This gives T=1200/(R2-R1)=1200/100=12 min. Answer B.
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Can we use relative speed method in this ques?

Their relative speeds = 200-100 = 100m/min
Time taken to meet for the first time = 1200/100 = 12mins
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Yes, you absolutely can. That's another quick and valid approach :thumbsup:
Natansha
Can we use relative speed method in this ques?

Their relative speeds = 200-100 = 100m/min
Time taken to meet for the first time = 1200/100 = 12mins
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