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Bunuel
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Bunuel
A student took a test in which 3 marks were given for each correct answer and 0.5 marks were deducted for an incorrect answer. If the test had 25 questions and the student attempted all the questions and got 40 marks in total, what is the difference between the number of correct and incorrect answers?

(A) 5
(B) 10
(C) 12
(D) 15
(E) 18

We can assign some variables for correct answers and incorrect answer.

x = correct
y = incorrect

Using the variables, we can assign a couple of equations based off the given information in the stem.

We know that 3 marks are given for each correct answer (x)

0.5 marks are deducted with each incorrect answer (y)

We are told that a total of 40 marks were given in total.

3x - 1/2y = 40 —> multiply whole equation by 2 to get rid of fraction.

6x - y = 80

To form our second equation, we are told that the test had a total of 25 questions. The student attempted each question on the test.

Correct + incorrect = 25 questions

Let us reformat our second equation in order to input a value for one of the variables back into our first equation.

x + y = 25
y = 25 - x

6x -(25 - x) = 80
6x -25 + x = 80

7x = 105
x = 15

Plugging x back into our equation to find the value of y.

y = 25 - x
y = 25 - 15
y = 10

Difference between the number of correct answers and incorrect answers.

x - y =
15 -10 = 5

Note: we can use the values for x and y to test that they work for either one of our equations.

x + y =
15 + 10 = 25

3x - 1/2y = 40
3(15) - 1/2(10) = 40
45 - 5 = 40

Option A

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