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06 Aug 2021, 03:15
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
64% (02:39) correct
36%
(02:36)
wrong
based on 149
sessions
History
Date
Time
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The sum of the highest common factor and the least common multiple of two positive integers is 680 and the least common multiple is 84 times the highest common factor. If one of the numbers is 56, then what is the value of the other ?
(A) 96
(B) 84
(C) 12
(D) 8
(E) 6
(A) 96
(B) 84
(C) 12
(D) 8
(E) 6
06 Aug 2021, 03:28
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Explanation:
HCF = a
LCM = 84a
84a + a = 680
85a = 680
a = 8
HCF = 8, LCM = 84x8 = 672
HCF x LCM = Product of two numbers
672 x 8 = 56 x 2nd Number
2nd number = 672/7 = 96
IMO-A
HCF = a
LCM = 84a
84a + a = 680
85a = 680
a = 8
HCF = 8, LCM = 84x8 = 672
HCF x LCM = Product of two numbers
672 x 8 = 56 x 2nd Number
2nd number = 672/7 = 96
IMO-A
06 Aug 2021, 04:30
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HCF + LCM = 680
LCM = 84*HCF
=> HCF + (84*HCF) = 680
=> HCF = 8
=> LCM = 84*8
HCF * LCM = Multiplication of the two numbers
Let's say the other number is x
=> 8*8*84 = 56*x
=> x = 96
OA should be A
LCM = 84*HCF
=> HCF + (84*HCF) = 680
=> HCF = 8
=> LCM = 84*8
HCF * LCM = Multiplication of the two numbers
Let's say the other number is x
=> 8*8*84 = 56*x
=> x = 96
OA should be A
