Bunuel
In a certain portfolio, the ratio of the number of domestic stocks to the number of foreign stocks is 7 to 2, and the ratio of the number of mutual funds to the number of foreign stocks is 2 to 3. If the ratio of the number of bonds to the number of domestic stocks is 4 to 3, what is the ratio of the number of mutual funds to the number of bonds?
(A) 28 to 9
(B) 14 to 3
(C) 9 to 28
(D) 7 to 1
(E) 1 to 7
Solution: We are given: The ratio of domestic stocks to foreign stocks is 7 to 2 and the ratio of mutual funds to foreign stocks is 2 to 3.
So we can write:
DS : FS = \(7:2\) and
MF : FS = \(2:3\)
In these 2 ratios, FS (foreign stocks) is common and we can make their ratios common too. The LCM of 2 and 3 is 6. So, we can write:
DS : FS = \(21:6\) and MF : FS = \(4:6\)Next, we have the ratio of the number of bonds to the number of domestic stocks is 4 to 3
So we can write:
DS : FS = \(21:6\) and
B : DS = \(4:3\)
In these 2 ratios, DS (domestic stocks) is common and we can make their ratios common too. The LCM of 21 and 3 is 21. So, we can write:
DS : FS = \(21:6\) and B : DS = \(28:21\)So ultimately we have the 3 ratios as:
DS : FS = \(21:6\)MF : FS = \(4:6\) and
B : DS = \(28:21\)We are asked the ratio of \(MF : B = 4:28 = 1:7\)
Hence the right answer is
Option E.