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Let the number of people being tested be 100.

We know 10% of those tested have Lepto, so of those being tested 10 will have it and 90 wont.

Positive: 10

There is a 90% chance that someone who is positive will get a positive test result, and 10% that they won't. From 10, 9 will test positive while 1 will test negative.

Negative: 90

There is a 20% chance that someone who is negative will get a positive test result, and 80% that they won't. From 90, 18 will get a positive result while 72 will get a negative test result.

Probability that a positive test is a positive case: \(\frac{Number of people who have Lepto}{Total number of positive tests}\)

Number of people who have lepto is 9. Total positive cases is 9+18 = 27.

\(= \frac{9}{27}\)

\(=1/3\)

Answer C
How number of people who have lepto is 9
It should be 10

Posted from my mobile device

If we assume total no. People = 100
Then 10%100= 10

However there’s two scenarios:

Case 1) PEOPLE W LEPO & TESTED POSITIVE:
Independent events:
Probability of selecting lepo: 10/100
Probability of that person testing positive: 90/100
p(L) * P(t) = 1/10*9/10= 9/100

So out of the 100 people, 9 will have lepo and will test positive

CASE 2) PEOPLE W NO LEPO & FALSE POSITIVE:
P of no lepo: 90/100
P of testing positive: 20/100
90/100*20/100= 18/100

So 18 people wont have lepo but will test positive.

Question asks for 9/27 =1/3
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Let total ppl = 1000

100 People have lepto. 90 test positive (90%), 10 test negative

900 people dont have lepto. 720 test negative (80%), 180 test positive.

positive cases that tested positive = 90.
Total positive cases = 90 + 180 = 270.

P = 90/270 = 1/3
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Have lepto AND result is positive: \((0.1)(0.9)\) -- (1) (favourable outcome)
Don't have lepto AND result is positive: \((0.9)(0.2)\)

Total probability of getting a +ve result: \((0.1)(0.9) + (0.9)(0.2) = 0.27\) -- (2) (total outcome)

Divide equation (1) by (2): \(\frac{0.09}{0.27} = \frac{1}{3}­\)­
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