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Bunuel
Every day John walks at a constant speed, V1, for 30 minutes. On a particular day, after walking for 10 minutes at V1, he rested for 5 minutes. He finished the remaining distance of his regular walk at a constant speed, V2, in another 30 minutes. On that day, find the ratio of V2 and his average speed (average speed is total distance covered divided by total time taken including resting time).

A. 1:1
B. 1:2
C. 2:3
D. 2:1
E. 3:2


Are You Up For the Challenge: 700 Level Questions
Deconstructing the Question
Theory: Distance = Rate × Time

1. Regular Walk:
* Speed = \(V_1\)
* Time = 30 minutes
* Total Distance (\(D\)) = \(30V_1\)

2. Particular Day Walk:
* Part 1: Walks at \(V_1\) for 10 minutes.
Distance covered = \(10V_1\).
Remaining Distance = \(30V_1 - 10V_1 = 20V_1\).
* Part 2 (Rest): Rests for 5 minutes.
* Part 3: Walks the remaining distance (\(20V_1\)) at speed \(V_2\) in 30 minutes.

Step 1: Calculate \(V_2\)
Since John covers the remaining \(20V_1\) distance in 30 minutes at speed \(V_2\):
\(V_2 = \frac{\text{Distance}}{\text{Time}} = \frac{20V_1}{30} = \frac{2}{3}V_1\).

Step 2: Calculate Average Speed (\(V_{avg}\))
Theory: Average Speed = Total Distance / Total Time
* Total Distance = \(30V_1\) (Same as the regular walk).
* Total Time = 10 min (walk) + 5 min (rest) + 30 min (walk) = 45 minutes.

\(V_{avg} = \frac{30V_1}{45} = \frac{2}{3}V_1\).

Step 3: Calculate the Ratio
We need the ratio of \(V_2\) to \(V_{avg}\):
\(\frac{V_2}{V_{avg}} = \frac{\frac{2}{3}V_1}{\frac{2}{3}V_1} = 1\).

The ratio is 1:1.

Answer: A
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