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11 Feb 2022, 03:07
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
56% (01:57) correct
44%
(01:45)
wrong
based on 150
sessions
History
Date
Time
Result
Not Attempted Yet
If #a denotes number of distinct factors of a, then #(#(#2340)) is equal to
A. 1
B. 2
C. 3
D. 4
E. 5
A. 1
B. 2
C. 3
D. 4
E. 5
11 Feb 2022, 03:14
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2340= \(2^2 * 3^2 * 5 * 13\)
No. of factors of 2340= (2+1)*(2+1)*(1+1)*(1+1)
= 3*3*2*2
= 36
Now, question reduces to #(#36),
36= \(2^2 * 3^2\)
No. of factors of 36= (2+1)*(2+1)
= 3*3
= 9
Now, question reduces to #9,
9=\( 3^2\)
No. of factors of 9= (2+1)
= 3
Hence, #(#(#2340))=3.
Option C. 3 is the correct choice.
No. of factors of 2340= (2+1)*(2+1)*(1+1)*(1+1)
= 3*3*2*2
= 36
Now, question reduces to #(#36),
36= \(2^2 * 3^2\)
No. of factors of 36= (2+1)*(2+1)
= 3*3
= 9
Now, question reduces to #9,
9=\( 3^2\)
No. of factors of 9= (2+1)
= 3
Hence, #(#(#2340))=3.
Option C. 3 is the correct choice.
