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23 Mar 2022, 08:05
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
71% (02:34) correct
29%
(02:36)
wrong
based on 293
sessions
History
Date
Time
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Not Attempted Yet
Attachment:
What is the value of.PNG [ 25.54 KiB | Viewed 4834 times ]
10 Apr 2022, 05:03
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We are free to plug in whatever values we want that don't put 0 in a denominator,so
Set a^(1/2) = 2
b^(1/2) = 1
Plugging in:
((2+1)/1)-(4/3))/(3+(1/3)) =
((9/3)-(4/3))/(3+(1/3)) =
(5/3)/(10/3) =
1/2
Posted from my mobile device
Set a^(1/2) = 2
b^(1/2) = 1
Plugging in:
((2+1)/1)-(4/3))/(3+(1/3)) =
((9/3)-(4/3))/(3+(1/3)) =
(5/3)/(10/3) =
1/2
Posted from my mobile device
10 Apr 2022, 10:47
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It's naturally possible to solve algebraically, but I'd use the approach Regor60 used above, since the algebra looks annoying. Faster still is to plug in a = 1 and b = 0, because then we just get (1 - 0)/(1 + 1) = 1/2.
