BrentGMATPrepNow
Bunuel
If \(a^3 − a^2 − a + 1 = 0\), what is the product of all possible values of a?
A. -1
B. 0
C. 1
D. 2
E. 4
We can factor the left side in parts.
Given:
a³ − a² − a + 1 = 0Factor in parts:
a²(a − 1) - 1(a - 1) = 0Combine to get:
(a² - 1)(a − 1) = 0Since the first expression (and brackets) is a difference of squares, we can factor it as follows:
(a + 1)(a - 1)(a - 1) = 0There are two unique solutions:
a = 1 and
a = -1, which means the product of all possible values of a = (
1)(
-1) =
-1Answer: AHey Brent, really nice solution here. I answered this question slightly differently by testing different integer values (starting with 0, then -1,1, then 2,-2 etc), so I realised that only 1 and -1 seemed to work, hence picked A.
I like your solution and was wondering if you have any tips on how to be able to develop an ability to spot opportunities to factorise like this? I would really like to try and develop such foresight, especially the part where (after factoring by parts), you noted that you could place a 1 outside the second component and make it -1(a-1) and then use difference of two squares, how can I learn / develop the ability to spot opportunities to do this?