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[color=#0f0f0f]1, 2, 3, 4, 5, 6, 7, 8, 9, 10

How many different ordered pairs of numbers (s, t) can be formed such that normal t = 3s, where s and t are numbers from the list above?

A. Two
B. Three
C. Five
D. Six
E. Ten

Why can only 3 pairs be made when the question is asking about different ordered pairs of (s, t)? I assume it is also asking for (t, s)?[/color]

Thank You

There are three ordered pairs:

s = 1 and t = 3
s = 2 and t = 6
s = 3 and t = 9

The question is asking only for the ordered pairs (s, t) where the relationship t = 3s holds, not for (t, s) pairs. In an ordered pair (s, t), the order matters—s is the first number, and t is the second. This means (s, t) is different from (t, s) unless s and t are the same number.
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