NOTE: In my opinion, this is not the best way to express the intended meaning of this question. Had I written it, I would have specified that "they start together at the start of the hour". Right now, who knows when the bells start tolling with respect to this one hour. Imagine the first joint toll 1 second before the start of this one-hour timer vs first joint toll right with the start of this one-hour timer. Answer would be 30 vs 31 in these situations.For now, assuming the intended meaning that the first toll happened just as this one-hour timer started, below is the detailed solution: Given:
- 5 bells toll at intervals of 5, 6, 8, 12, and 20 seconds, respectively.
- They start together (imagine a timer starting with the first toll of all these bells).
To find: How many times all five bells toll together in one hour
Solution:Step 1: Find the LCM of the intervals
The LCM will tell us after how many seconds all the bells toll together again (for the first time after starting).
Prime factorizations:
- 5 = 5
- 6 = 2 × 3
- 8 = \(2^3\)
- 12 = \(2^2\) × 3
- 20 =\( 2^2\) × 5
So, LCM = \(2^3\) × 3 × 5 = 120 seconds
This means all the bells toll together every 120 seconds, i.e.,
every 2 minutes.
Step 2: Count how many such intervals fit in 1 hour
1 hour = 60 minutes
So, there are 60 ÷ 2 =
30 such 2-minute intervals in 60 minutes.
Step 3: Include the starting time
They toll together at
time 0, and then after every 2 minutes
Thus, they toll together
31 times in total in that one hour.
Correct Answer: (C)Shweta KoshijaGMAT, GRE, SAT, AP Calculus Coach for 10+ years