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23 May 2022, 08:45
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
61% (01:17) correct
39%
(01:29)
wrong
based on 242
sessions
History
Date
Time
Result
Not Attempted Yet
How many integers are divisible by 4 are there between 8! and 8! + 20 inclusive?
A. 4
B. 5
C. 6
D. 7
E. 8
A. 4
B. 5
C. 6
D. 7
E. 8
23 May 2022, 09:12
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Solution:
8!=8*7*6*5*4*3*2*1=40320
8!+20=(8*7*6*5*4*3*2*1)+20=40340
→numbers between 40320 and 40340 which is divided by 4 are
40320, 40324, 40328, 40332, 40336, 40340.
Hence, total 6 numbers which are divided by 4.
C is the correct option.
Posted from my mobile device
8!=8*7*6*5*4*3*2*1=40320
8!+20=(8*7*6*5*4*3*2*1)+20=40340
→numbers between 40320 and 40340 which is divided by 4 are
40320, 40324, 40328, 40332, 40336, 40340.
Hence, total 6 numbers which are divided by 4.
C is the correct option.
Posted from my mobile device
23 May 2022, 09:21
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Bunuel
8! is clearly divisible by 4, as 8! = 8*7*6*5*4*3*2*1
8!+4 is divisible by 4.
So 8!+4 is divisible by 4.
And 8!+8 is divisible by 4.
And 8!+12 is divisible by 4.
And 8!+16 is divisible by 4.
And 8!+20 is divisible by 4.
That's six.
Answer choice C.
