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29 May 2022, 09:00
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
55% (02:52) correct
45%
(02:14)
wrong
based on 75
sessions
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Not Attempted Yet
All the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 are written in a 3*3 array of squares, one number in each square, in such a way that if two numbers are consecutive then they occupy squares that share an edge. The numbers in the four corners add up to 18. What is the number in the center?
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Are You Up For the Challenge: 700 Level Questions
(A) 5
(B) 6
(C) 7
(D) 8
(E) 9
Are You Up For the Challenge: 700 Level Questions
29 May 2022, 11:18
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Bunuel
Two ways: logic and just testing for a possible solution.
Since each digit shares an edge with the digits immediately less than and greater than itself, the edges mean that when we move to the next square, we alternate between even and odd, eventually forming a chessboard pattern. There are five odd digits and four even ones and four even ones, so the odds need to go in the four corners plus the center. The five odd digits add to 1+3+5+7+9=25 and we are told that the corners add to 18, so the center must be 7.
Answer choice C.
If we didn't spot all that, we could just draw it out and put in numbers. On a single try, we would be guaranteed to have the correct answer (well, unless you tried putting an even number in a corner/middle or an odd number on one of the other squares, in which case you'd need to try again, but I think the vast majority of people would start with a 1 in a corner square).
