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Bunuel
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Bunuel can you help?
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In this question, the best approach is elimination imo.
Since, the maximum value p(a)*p(b) can take is 1/2, option D and E are eliminated.
Secondly, the least value that p(a)*p(b) can take is -> ( 3/4+1/2) - 1 = 1/4, so option A and B are eliminated and we are left with C as the answer.
Hope this helps.

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Jshellypp
I dont even know where to start with this one. Can anyone break it down? I dont even get how the explanation above even started.
­Hi

Let me answer my approach

1 = P(AUB) + P(A'∩B') [i am considering P(A'∩B') here since it is not mentioned in the question at least one event occurs]
1 = P(A)+P(B)-P(A∩B)+P(A'∩B')
1 = 3/4 + 1/2-P(A∩B)+P(A'∩B')
1 - 5/4 = -P(A∩B)+P(A'∩B')
1/4 = P(A∩B)-P(A'∩B')
1/4+P(A'∩B') = P(A∩B)

for P(A∩B) to be minimum P(A'∩B') must be minimum, considering P(A'∩B') as 0 => 1/4 = P(A∩B)
also from the question we have P(A) as 3/4 & P(B) as 1/2 so the Maximum value of P(A∩B) is 1/2

0.25<= P(A∩B) <= 0.5

as per the options C suits
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How did you calculate the least value?
Dhananjayrai
In this question, the best approach is elimination imo.
Since, the maximum value p(a)*p(b) can take is 1/2, option D and E are eliminated.
Secondly, the least value that p(a)*p(b) can take is -> ( 3/4+1/2) - 1 = 1/4, so option A and B are eliminated and we are left with C as the answer.
Hope this helps.

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