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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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Subtract 12 from each of the three numbers 1356,1868 and 2764 . We get the numbers that is completely divisible by the divisor . 1356 - 12 = 1344 , 1868 -12 = 1844 and 2764-12 = 2752 . Now determine the GCF of 1344 , 1856 and 2752 . While taking LCM start with 8 or 16 if you are comfortable with it . You will get 64 as the answer.
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The greatest number which can divide 1356, 1868 and 2764 leaving the same remainder 12 in each case

Since, all the numbers are leaving 12 as the remainder so let's start by subtracting 12 from each number.

1356 - 12 = 1344
1868 - 12 = 1856
2764 - 12 = 2752

Now, the number which will decide all these numbers will be the GCD of HCF of these numbers

Attachment:
GCD.jpg
GCD.jpg [ 25.85 KiB | Viewed 1463 times ]

=> All these numbers will be divisible by the GCD which is 4*4*4 = 64

So, Answer will be A
Hope it helps!

Watch the following video to MASTER LCM and GCD

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We can calculate the HCF of 1356, 1868, 2764 by difference method
First Difference
1868- 1356 = 512
2764 - 1868 = 896
Second Difference
896 - 512 = 384
HCF will be the Factor of 384. So 64 X 6 = 384 or
Only 64 can divide 384 in the options. So, Option A is Correct.
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