Bunuel
If \(x > y\), then which of the following could be true?
I. \(|x|*|y|*x < |x*y|*y\)
II. \(|x|*|y|*x > |x*y|*y\)
III. \(|x|*|y|*x = −|x*y|*y\)
(A) I only
(B) II only
(C) III only
(D) I and II only
(E) II and III only
For could be true, we only need to find one true condition and that is enough to state that this statement could be true
If x>y, it can imply the following conditions (valid for both integers as well as for fractions):
i) x and y both are negative
ii) x and y both are positive
iii) x is positive and y is negative
I. \(|x|*|y|*x < |x*y|*y\)
We can already see that if both x and y are the same sign and integers then this will obviously never satisfy because x > y and there are 2 (x) on the left and 1 on the right.
We can see for fractions and see if it works out
If x=1/2 and y=1/4 then we get 1/16 < 1/32 which is FALSE
If x=-1/2 and y=-1/4 then we get -1/32 < -1/16 which is also FALSE
If x=1/2 and y=-1/2 then we get Positive < Negative which is also FALSE
So, this statement cannot be trueII. \(|x|*|y|*x > |x*y|*y\)
This is reverse of the previous statement, and since that gave false for all, we can take any one example from that and it will give true
If x=1/2 and y=1/4 then we get 1/16 < 1/32 which is TRUE
So, this statement can be trueIII. \(|x|*|y|*x = −|x*y|*y\)
Since there is equal to sign, we need to try equal absolute values and let us try x as positive and y as negative because there is a negative sign involved in the RHS of the equation
If x=1/2 and y=-1/2 then we get 1/8 = -(1/4)*(-1/2) which is TRUE
So, this statement can be trueSo, II and III can be true
Answer - E