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16 Nov 2022, 11:37
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
69% (01:57) correct
31%
(02:44)
wrong
based on 16
sessions
History
Date
Time
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Not Attempted Yet
An isosceles triangle has sides of length x, 2x and 2x. If the area of the triangle is 25√15, what is the value of x?
A. √15
B. 2√15
C. 10√15
D. 5
E. 10
A. √15
B. 2√15
C. 10√15
D. 5
E. 10
16 Nov 2022, 11:57
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File comment: Answer is option E
IMG_20221117_002632__01.jpg [ 1.97 MiB | Viewed 3961 times ]
16 Nov 2022, 12:30
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An isosceles triangle has sides of length x, 2x and 2x. If the area of the triangle is 25√15, what is the value of x?
Solution:-
here the side are x , 2x and 2x
if we put the perpendicular to base then it will bisect the base in 2 equal part
so perpendicular =sqrot(4x^2-x^2/4)
=sqrot(15x^2/4)
so area is 1/2*x*(sqrot(15)x/2)
25sqort15=1/4(sqrot(15)X
x=10
Solution:-
here the side are x , 2x and 2x
if we put the perpendicular to base then it will bisect the base in 2 equal part
so perpendicular =sqrot(4x^2-x^2/4)
=sqrot(15x^2/4)
so area is 1/2*x*(sqrot(15)x/2)
25sqort15=1/4(sqrot(15)X
x=10
