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Deconstructing the Question

We need to find the number of 3-digit integers (between 100 and 1,000) that satisfy three specific conditions for each digit.

1. Hundreds Digit (Must be Even)
The hundreds digit of a 3-digit number cannot be 0.
Possible even digits: {2, 4, 6, 8}
Total options = 4

2. Tens Digit (Must be Odd)
Possible odd digits: {1, 3, 5, 7, 9}
Total options = 5

3. Units Digit (Non-zero and divisible by 3)
Digits divisible by 3 are {0, 3, 6, 9}.
Since it must be "non-zero", the possible digits are: {3, 6, 9}
Total options = 3

4. Total Combination
Using the Fundamental Counting Principle, we multiply the number of options for each position:
\(Total = 4 * 5 * 3 = \) 60

The correct answer is D.
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