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03 Jan 2023, 09:00
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
63% (03:21) correct
37%
(03:26)
wrong
based on 68
sessions
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Chloe, Jen and Patricia gave three tests in a row. Chloe’s score in her first test is equal to the sum of Jen’s score in her first test and Patricia’s score in her second test. Chloe’ score in her third test is equal to the sum of scores obtained by Patricia in her third test and score obtained by Jen in her second test. Chloe got an equal score in all her three tests and the total score in all three tests is equal to the combined total obtained by Jen and Patricia in all the three tests.
If the scores obtained by Chloe, Jen and Patricia are added the resultant is p, what is the maximum score that Jen could get in her first test if none of the scores are negative?
A. p/2
B. p/3
C. p/4
D. p/6
E. p/8
If the scores obtained by Chloe, Jen and Patricia are added the resultant is p, what is the maximum score that Jen could get in her first test if none of the scores are negative?
A. p/2
B. p/3
C. p/4
D. p/6
E. p/8
03 Jan 2023, 21:43
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Bunuel
Chloe got an equal score in all her three tests
Let the three scores of Chloe, Jen and Patricia be c, c, c; j1, j2, j3; and t1, t2, t3
Chloe’s score in her first test is equal to the sum of Jen’s score in her first test and Patricia’s score in her second test
=> c = j1 + t2 --- (i)
Chloe’ score in her third test is equal to the sum of scores obtained by Patricia in her third test and score obtained by Jen in her second test
=> c = t3 + j2 --- (ii)
The total score of Chloe in all three tests is equal to the combined total obtained by Jen and Patricia in all the three tests.
=> c + c + c = (j1 + j2 + j3) + (t1 + t2 + t3) --- (iii)
If the scores obtained by Chloe, Jen and Patricia are added the resultant is p
=> (c + c + c) + (j1 + j2 + j3) + (t1 + t2 + t3) = p
From (iii):
c + c + c + c + c + c = p
=> c = p/6
We need to find the greatest possible value of j1
From (i): c = j1 + t2 => j1 = c - t2
=> The greatest value of j1 = c = p/6
(when t2 = 0, since no score is negative)
Answer D
12 May 2024, 02:32
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