stneQuote:
it doesn't mean in the exam I am going to make a table and solve this question. It's just there to make the solution easier to understand.
Apologies. When you said "Not sure why you would even try to find one...Even if you are able to devise an equation...it's best to proceed in a non-formulaic way", to me it meant that it does mean you are going to make a table to solve this question, not that it is only there for the question to be easier to understand.
Also not sure if you perceive that we are arguing as my initial question was simply "is there a simple equation to solve without needing to write out a table?". The answer could have been "no" or "if there is i'm not aware of it. The table was faster for me". I also asked because I was trying to determine the equation myself to get a better understanding but got a couple of different answers so i thought maybe you had one. Unfortunately i do not follow your account to know whether or not you "Have you seen me using a table for all my posts".
Here's the equation, only lightly confirmed by a friend with more math background:
To determine the value in each account we do this:
Total = Principal * Rate^Frequency
Y = 1000*2^(n/14)
X = 1000*2^(n/7) - 500*2^(n/7 - 1) --> we subtract 1 because we do not remove 500 from the initial deposit
Adding together we get:
1000*2^(n/14) + 1000*2^(n/7) - 500*2^(n/7 - 1) > 40000
Divide by 500:
2 * 2^(n/14) + 2 * 2^(n/7) - 2^(n/7-1) > 80
2^(n/14 + 1) + 2^(n/7 + 1) - 2^(n/7-1) > 80
Now for easier math and testing of numbers, lets instead assume n is in 14 year chunks and abstract the equation:
2^(n+1) + 2^(2n+1) - 2^(2n - 1) > 80
We see here that 2 < n < 3 because if
n = 2 (28 years) --> 2^3 + 2^5 - 2^3 = 32
n = 3 (42 years) --> 2^4 + 2^7 - 2^5 = 112
and we are looking for the minimum number that gets us 80. This limits us to options B and C and since it cannot be B because 32 < 80, it must be C
Hope it helps.