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Three pipes, A, B and C are opened to fill an empty tank such that A and B cam fill the tank alone in 36 minutes and 45 minutes respectively and C can empty it in 30 minutes. After 6 minutes the emptying pipe is closed. In how many minutes the tank will be filled ?
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Bunuel
Three pipes, A, B and C are opened to fill an empty tank such that A and B cam fill the tank alone in 36 minutes and 45 minutes respectively and C can empty it in 30 minutes. After 6 minutes the emptying pipe is closed. In how many minutes the tank will be filled ?

A. 18
B. 20
C. 24
D. 25
E. 30
Solution:

  • Let the work be 180 (LCM of 36, 45 and 30)
  • Rate of A \(=\frac{Work}{Time}=\frac{180}{36}=5\)
  • Rate of B \(=\frac{Work}{Time}=\frac{180}{45}=4\)
  • Rate of C \(=\frac{Work}{Time}=\frac{180}{30}=-6\) (negative because pipe C is used to empty the tank)
  • Let the time needed to fill the tank be t mins
    Attachment:
    wrtt.png
    wrtt.png [ 3.32 KiB | Viewed 5302 times ]
  • According to the question, \(5t+4t-36=180\) or \(t=24\)

Hence the right answer is Option C
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What has been asked is ambiguous, rightly pointed out by ThatDudeKnows
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Three pipes, A, B and C are opened to fill an empty tank such that A and B cam fill the tank alone in 36 minutes and 45 minutes respectively and C can empty it in 30 minutes. After 6 minutes the emptying pipe is closed. In how many minutes the tank will be filled ?

I followed the same approach . However you'll also need to add the additional 6 mins to 18. Hence total time is T = 6+18 = 24 mins.
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