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007saisurya
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There are 2 cases - 1 women , 1men or 2 women
(5C1*8C1 + 5C2 )/ 13C2 = ((5*4 )+ 5 )/ (13*3) = 25/39
007saisurya
Out of 13 applicants for a job, there are 5 women and 8 men. Two persons are to be selected for the job. The probability that at least one of the selected persons will be a woman is:

A.16/39
B.34/39
C.25/39
D.16/53
E.27/53
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This is an "at least one" probability problem, and the fastest way to solve these is using the complement trick:

P(at least one woman) = [b]1 - P(NO women)[/b]

P(NO women) means BOTH selected persons are men.

Step 1: Find total ways to choose 2 people from 13.
C(13,2) = (13 × 12) / (2 × 1) = 78

Step 2: Find ways to choose 2 men from 8 men (this is the "no women" scenario).
C(8,2) = (8 × 7) / (2 × 1) = 28

Step 3: P(no women) = 28/78 = 14/39

Step 4: P(at least one woman) = 1 - 14/39 = 25/39

Answer: C

Why use the complement? "At least one woman" includes 2 separate cases — exactly 1 woman OR exactly 2 women. Calculating both and adding them works, but it's slower. The complement ("no women at all") is just one simple case, so subtracting it from 1 is much faster.

General principle: Whenever you see "at least one" in a probability question, immediately think complement. Calculate the probability of the opposite event (none), and subtract from 1. This shortcut saves significant time on the GMAT.

The most common mistake here is forgetting to use combinations and instead just multiplying individual probabilities incorrectly. Always count the combinations carefully: total outcomes in the denominator, favorable outcomes in the numerator.
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