Last visit was: 23 Apr 2026, 21:57 It is currently 23 Apr 2026, 21:57
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Shubhradeep
Joined: 11 Jan 2024
Last visit: 07 Feb 2026
Posts: 120
Own Kudos:
247
 [25]
Given Kudos: 108
Location: India
Posts: 120
Kudos: 247
 [25]
1
Kudos
Add Kudos
24
Bookmarks
Bookmark this Post
User avatar
madhuri14
Joined: 27 Oct 2023
Last visit: 14 Aug 2025
Posts: 4
Own Kudos:
4
 [4]
Given Kudos: 11
Posts: 4
Kudos: 4
 [4]
3
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
Shubhradeep
Joined: 11 Jan 2024
Last visit: 07 Feb 2026
Posts: 120
Own Kudos:
Given Kudos: 108
Location: India
Posts: 120
Kudos: 247
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
sset92
Joined: 02 Dec 2020
Last visit: 19 Mar 2026
Posts: 20
Own Kudos:
Given Kudos: 22
Posts: 20
Kudos: 76
Kudos
Add Kudos
Bookmarks
Bookmark this Post
The question says that the students of the school have to select at least 2 subjects from the pool of 3 subjects. This means that Only Math = 0, Only Chem = 0, Only Physics = 0.
Let us call the number of students who have taken all three as k, and k = 18 (Given).

Let us consider, those who have taken both Math and Physics only as p, Math and Chem only as q, and Physics and Chem only as r.

It is given in the question the number of students who have selected Mathematics as one of their selections is 23.
Therefore p+q+k=23
Since k = 18
Therefore, p+q=5

It is also given that number of students who have selected Physics as one of their selections is 25.
Therefore p+r+k=25
p+r=7

Subtract : (p+r)-(p+q) = 7-5
Therefore: r-q=2

We need to find minimum number of students who have taken chem. We know chem is r+k+q.
We also know that k = 18 and that r>q (r-q=2)

Since we can not change k, and considering r>q and can not be minimised below q, so only q can be made minimum which in this case can be 0 if r = 2.

With that we get Minimum students in Chem as r+k+q = 2+18+0 = 20.­
User avatar
kanikaa9
Joined: 19 Aug 2023
Last visit: 02 Jul 2025
Posts: 90
Own Kudos:
Given Kudos: 708
Location: India
WE:Consulting (Consulting)
Posts: 90
Kudos: 55
Kudos
Add Kudos
Bookmarks
Bookmark this Post
n(All 3) = 18
n(M) = 23
n(P) = 25
n(C) = minimize

so maximise n(M + P) = 23 (all maths kids chose physics)
which leaves out 2 (25-23) as the kids who chose chem

so total chem is 18 + 2 = 20 (D)
Moderators:
Math Expert
109787 posts
Tuck School Moderator
853 posts