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gmatophobia

Bunuel
­If the greatest common factor of the integers \(\frac{n}{11}\) and \(\frac{n}{13}\) is 6, what is the number of positive factors of the positive integer \(n\)?

A. 2
B. 4
C. 6
D. 8
E. 16­

 
­
\(n = 11 * 13 * 6\)

\(n = 11^1 * 13^1 * 2^1 * 3 ^1\)

\(n = 2 * 2 * 2 * 2 = 16\)

Option E
­I followed your reasoning until the second step but what is that last step? I was under the impression that the factors would be 1, 2, 3, 11, 13, and the number itself, so 6, but understand now that 33, 39 could be a factor etc.
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envy5
­I followed your reasoning until the second step but what is that last step? I was under the impression that the factors would be 1, 2, 3, 11, 13, and the number itself, so 6, but understand now that 33, 39 could be a factor etc.
envy5 - You can refer to the below article on the method to find the number of positive factors of an integer


­Finding the Number of Factors of an Integer

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.­


Reference - [url]https://gmatclub.com/forum/math-number-theory-88376.html­[/url]­
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