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Shreya1211
Bunuel GMATNinja explanation please?

(I selected A)
­Remember that the pool of letters includes not one but TWO letter A's­, which we can think of as A(1) and A(2).

The 7! options include two distinct options that spell MANDIRA:

  1. MA(1)NDIRA(2)
  2. MA(2)NDIRA(1)

So the numerator needs to be 2 (2!=2) and not 1.­
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Hi GMATNinja is it not 2*2/7! given that MANDIRA has two ways of being formed due to the 2 As?
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Shreya1211
Bunuel GMATNinja explanation please?

(I selected A)
­Remember that the pool of letters includes not one but TWO letter A's­, which we can think of as A(1) and A(2).

The 7! options include two distinct options that spell MANDIRA:

  1. MA(1)NDIRA(2)
  2. MA(2)NDIRA(1)

So the numerator needs to be 2 (2!=2) and not 1.­
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Arungmat612
­The letters of the word MIRANDA are shuffled. What is the probability that the new word formed is MANDIRA?

A. 1/7!
B. 2!/7!
C. (2!2!)/7!
D. 12/7!
E. 2/6!­

No need to overcomplicate this—it’s an easy question. There are seven letters in MIRANDA, with A repeating twice. The total number of different words that can be formed by arranging these letters is 7!/2!. Only one of those arrangements will be MANDIRA, so the probability is 1/(7!/2!) = 2!/7!.

Answer: B.
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