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The temperature of the room is measured using a thermostat. According to the thermostat, the temperature C(t) + -0.2 (t-a)^2 + 50, where 0≤ t ≤ 24 and a>0. If at 2:00 am. the temperature of the room is 30 degree Celsius, the according to the thermostat at what time does the room have the maximum temperature.
A. 10:00 AM
B. 11:00 AM
C. 12:00 PM
D. 1:00 PM
E. 2:00 PM
Pls help me
To determine the time at which the room has the maximum temperature according to the given function:
C(t) = -0.2(t - a)^2 + 50### Given:
- The function for temperature:
C(t) = -0.2(t - a)^2 + 50- The temperature at 2:00 AM (which we can denote as
t = 2):
C(2) = 30### Step 1: Find the value of [a]
Substituting
t = 2 into the temperature function:
C(2) = -0.2(2 - a)^2 + 50 = 30Now, we can solve for [a]:
-0.2(2 - a)^2 + 50 = 30-0.2(2 - a)^2 = 30 - 50-0.2(2 - a)^2 = -20(2 - a)^2 = -20/-0.2 = 1002 - a = + or - 10This gives us two possible equations:
1.
2 - a = 10 →
a = -8 (not valid since
a > 0)
2.
2 - a = -10 →
a = 12### Step 2: Determine the maximum temperature
The function
C(t) = -0.2(t - 12)^2 + 50 is a downward-opening parabola, and its maximum occurs at the vertex, which is at
t = a = 12.
### Conclusion
Thus, the maximum temperature occurs at:
12:00 PM (noon)### Answer:
C. 12:00 PM