Addu.23
I'm confused with this line "Tap 2 fills the same tank with water at a rate X times as fast as Tap 1". Doesn't this mean Tap 2 = xT1 + T1?
Such lines are a weak point for me. Can someone share a list of such lines and it's equation or provide a link to such a list? In my notes I have these 2 lines:
'A's speed is 1.5 times B's speed' -> a=1.5b
'A's speed is 1.5 times faster than B's speed' -> a= 1.5b + b
Bunuel would appreciate if you can help here
Here's a few cents from my side to brainstorm a little bit.
Assuming you understood the grammatical aspects that troubled you. So, my inputs is only for conceptual aspect. Hope you don't mind.
Quesiton is:
Tap 1 takes 1.5 hours to fill a certain tank with water. Tap 2 fills the same tank with water at a rate X times as fast as Tap 1. Tap 1 and Tap 2 together take 15 minutes to fill the same tank with water. Find the value of X.
A. 1/9
B. 1/5
C. 5
D. 9
E. 45
Conceptually, you see that 2 fills the tank X times that of 1 i.e. X >=1 (X = 2 or 3 or 4 or 5.... so on if we consider integer only to avoid the complexity of fractions). And we don't need to calculate.
Now, if 1 takes 6 times(90/15) the time that 1 and 2 together take to fill the tank then that means that speed of filling the tank by the two taps too would make a sum of 6. And in this sum of 6, 1 part belongs to Tap 1 and rest 5 parts belong to Tap 2. Just that you have to know that here speed and time are inverse to each other so X has to be chosen.
Hence X = 5. Here we have our answer.Solution by equation : Let 100 is work i.e. total tank water that fill it.
So, Speed of Tap 1 = \(\frac{100}{90}\)
Speed of Tap 2 = \(\frac{100X}{90}\)
Solving for equation
\(\frac{Total Water }{ Speed of Tap 1 + Speed of Tap 2} = 15\)
\(100/(\frac{100}{90} +\frac{100X}{90}) = 15\)
X = 5
So, Tap 2 was 5 times faster than Tap 1.
OR
Tap 2 filled \(\frac{5}{6}^{th}\) part of the tank and Tap 1 \(\frac{1}{6}^{th}\).
Similarly, If you just replace 15 by any number ( if a factor of 90 it is better) you would get X's value accordingly.
Like if we replace 15 by 30 then X = 2, meaning 2's speed was twice that of 1's. Here Tap 1 would have taken 3 times the time the two together would have taken.
Point is the slower tap makes only 1 part of the total parts that we may get. Will leave upto you to do calculations for the non factor of 90.
Note: Among the choices we have A and B are not possible since it would have made Tap 2 slower than Tap 1 because Tap 2's speed cannot be less than 1 already. And you can put C,D or E values to solve for 15 minutes.
Hope this helps.