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Bunuel
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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julemirza
I am confused I tried to use the sum of a geometric sequence formula for this Sn = (a(r^n -1))/ r- 1
However the result then gives me 378 when n is 6

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We need the "n"th term and not sum of terms, as we have been asked the number after 4 years.

If we sum them with n=6, we basically get a 6 * (2^5 + 2^4...+ 2^1 + 1) = 378, but all we want is the 6th term of the series while considering the 0th term is 6. That would be 6 * 2^6 = 384, which is obviously 6 more than the series above.
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julemirza
I am confused I tried to use the sum of a geometric sequence formula for this Sn = (a(r^n -1))/ r- 1
However the result then gives me 378 when n is 6

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When you use geometric series for this, n should be 7.

First term is 6 and then there are 6 more terms. So total 7 terms in the G.Series.

Also, we need \(n^{th}\) term not Sum of terms.
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Maisie decides to stock rabbits at her pet store, unaware that rabbit populations double every eight months. If she starts with 6 rabbits, how many rabbits will she have in 4 years, if none of them are sold or die during this period?

A. 96
B. 192
C. 256
D. 324
E. 384

1) Our final value will be 6*2^x , where x is equivalent to the 8-month periods which the population doubles.
2) 4 years = 4* 12 months = 48 months. ->> 48 months/ 8 months = 6 periods.
3) Finally, 6*2^6= 6*64= 384 ->> Answer E
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> 1 rabbit Became $2=2^1$ times in $8$ months
> 1 rabbit Became $2^{6}$ times in $8\times6=48$ months
> 6 rabbit Became $2^{6}\times6=384$ in $48$ months
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