Let the number of $50, $100 and $500 notes with Amy be x,y and z respectively.
Since the total amount is $2400, it can be written as:-
50x + 100y + 500z = 2400
x + 2y + 10z = 48Now, the total number of notes with Amy is x+y+z. Out of these, she gives away 5 notes as school fee such that she is left with minimum pocket money.
How to minimize pocket money?Pocket money + school fee = $2400
Pocket money = $2400 - (school fee)
Min.(Pocket Money) = $2400 - max.(school fee)
Hence, to minimize the pocket money, we have to maximize the school fee.
How to maximize school fee?Case I:Maximum value of school fee would be if all the 5 notes given away as school fee are of $500 denomination i.e. the highest denomination.
However, z can not be equal to 5 as x+2y+10z = 48 (if z=5, then x+2y+10(5) > 48)
Case II:Now, we look at the next best possible option to maximize the school fee i.e. 4 notes of $500 denomination (highest denomination) and 1 note of $100 denomination (second highest denomination).
It means y=1 and z=4.
Testing these values in the condition x+2y+10z = 48, we get x = 6.
This gives us valid values of x,y and z.
Therefore, the maximum value of school fee = 4*$500 + 1*$100 = $2100
Minimum value of pocket money = $2400 - $2100 = $300
Correct option is (B).
Bunuel
Amy had $2400, which comprises of her school fee and her pocket money. The amount was in denominations of $50, $100 and $500 notes. She gave 5 notes at her school fee counter. What is the minimum possible amount that she got as her pocket money if the number of $500 notes is greater than the number of $100 notes which in turn was less than the number of $50 notes?
A. $250
B. $300
C. $350
D. $400
E. None of these