A certain factory has a defect rate of r defective items for every

Question

A certain factory has a defect rate of r defective items for every c items it produces. All defective items are sent to storage at a cost of d cents per item. If the factory produces 3,600 items in a given month, what are the storage costs, in cents, for that month?

A.  \frac{3600d}{r}

B.  \frac{3600rd}{c}

C.  3600rd

D.  \frac{3600rc}{d}

E.  \frac{3600cd}{r}

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skry209 · Answer

Total Defective items = (3600/c)*r
Storage costs = total defective items * cost for storage for each item
Storage costs = 3600*r*d/c

Ayeka · Answer

There are r defective items for every c items produced. 
Cost of sending defective items to storage= d
Cost of sending r defective items (for every c items produced) to storage= (r/c)*d
Total defective items = 3600
Storage costs= (3600*r*d)/c

Answer: B

keets02 · Answer

for every c items r are defective
  c -> r 
for 3600 how many
 3600 -> ?

Using cross multiplication
  c-> r 
 3600 -> x

x = (3600 * r)/ c items are deffective

cost per item=d

total cost for the month =(3600*r)*d )/c = 3600rd/c

Answer:  Option B

akshatcy · Answer

Given: Items produced by factory (c) = 3600

Let's assume, defective items (r) = 600
Cost to send back each defective item (d) = 1 cent
Therefore, cost to send back 600 defective items = 600 cents

We need to substitute following values in options to find the storage cost as 600.
c = 3600, r = 600, d =1

Looking at the options C, D & E can be eliminated as values will be much greater than 600.

Solving for A =  \frac{3600d}{r}  =  \frac{3600(1)}{600}  = 6

Solving for B =  \frac{3600rd}{c}  =  \frac{3600(600)(1)}{3600}  = 600

Answer (B)

prantorboni · Answer

A certain factory has a defect rate of r defective items for every c items it produces. All defective items are sent to storage at a cost of d cents per item. If the factory produces 3,600 items in a given month, what are the storage costs, in cents, for that month?

For each 3600/r unit of items company has a  defect rate of r defective items. So, the total defective items are,

3600/c x r

Now, all defective items are sent to storage at a cost of d cents per item. So, total storage cost would be,

3600r/c x d 
 = 3600rd/c

Answer:   B.   3600  r  d/  c.

sushanth21 · Answer

Total Defective items = (3600)r/c 
 Storage costs = total defective items * cost for storage for each item 
 Storage costs = 3600rd/c

A certain factory has a defect rate of r defective items for every

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A certain factory has a defect rate of r defective items for every

Prep Toolkit

615 to 715 in 15 Days (Ria's Strategies)

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745 with Only Self-Prep and GMAT Club

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Perfect 805 Score Debrief by Julia

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