Last visit was: 24 Apr 2026, 12:06 It is currently 24 Apr 2026, 12:06
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
kingbucky
Joined: 28 Jul 2023
Last visit: 22 Apr 2026
Posts: 498
Own Kudos:
Given Kudos: 329
Location: India
Products:
Posts: 498
Kudos: 585
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
stne
Joined: 27 May 2012
Last visit: 23 Apr 2026
Posts: 1,809
Own Kudos:
Given Kudos: 679
Posts: 1,809
Kudos: 2,090
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
kingbucky
Joined: 28 Jul 2023
Last visit: 22 Apr 2026
Posts: 498
Own Kudos:
Given Kudos: 329
Location: India
Products:
Posts: 498
Kudos: 585
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Krunaal
User avatar
Tuck School Moderator
Joined: 15 Feb 2021
Last visit: 21 Apr 2026
Posts: 853
Own Kudos:
912
 [1]
Given Kudos: 251
Status:Under the Square and Compass
Location: India
GMAT Focus 1: 755 Q90 V90 DI82
GPA: 5.78
WE:Marketing (Consulting)
Products:
GMAT Focus 1: 755 Q90 V90 DI82
Posts: 853
Kudos: 912
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Total Engineers = Experienced engineers (\(E_e\)) + Beginner engineers (\(B_e\)) .........(i)

\(\frac{E_e }{ B_e} = \frac{2k}{9k}\) ........(ii)

\(\frac{2k + 8 }{ 9k} = \frac{2 }{ 5}\)

Solving we get k = 5

From (i) and (ii),

Total Engineers = 2k+9k = 11k = 11*(5) = 55

Answer E.
User avatar
stne
Joined: 27 May 2012
Last visit: 23 Apr 2026
Posts: 1,809
Own Kudos:
Given Kudos: 679
Posts: 1,809
Kudos: 2,090
Kudos
Add Kudos
Bookmarks
Bookmark this Post
kingbucky
But, the question says that IF 8 experienced workers join, the ratio becomes....
It does not say that 8 experienced workers joined, and the ratio became...

That is, in an imaginary situation, where in if 8 workers join, the ratio will become....

stne
kingbucky
In a particular robotics workshop, the ratio of the number of experienced engineers to the number of beginner engineers is 2 to 9. If 8 additional experienced engineers join the workshop, the ratio becomes 2 to 5. How many engineers are in the workshop?

(A) 5
(B) 14
(C) 35
(D) 50
(E) 55

kingbucky, Thank you for the question.

Please check the answer choices or the question. Total engineers at the end should be a multiple of \(7,\) however option E (OA ) is not a multiple of \(7\).

We have option B and option C as multiple of \(7,\) however before the addition of \(8\) additional experienced engineers,the total engineers should be a multiple of \(11.\)

However when we remove \(8\) from option B and option c we get \(6\) and \(27\), respectively, none of which are multiple of \(11\).

Hence please check the question. Thank you.
ok . now I see your point.

I feel question is a bit ambiguous. How are we to know whether the # of enginners being asked is after the joining or before the joining?

Better: How many engineers were initially in the workshop?
Moderators:
Math Expert
109818 posts
Tuck School Moderator
853 posts