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I keep getting (-1)^1 + (-1)^2 + (-1)^3 + (-1)^5 + (-1)^7 ... up til the 61st prime which is not equal to -1.

After (-1)^1 + (-1)^2 , you are left with the summation of -1's up to the 61st prime, what am I missing in this one MartyMurray?
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hejwej
Am i misinterpreting what ADD means? is the question not asking us to: -1+1+(-1)+(-1)+(-1).....= ???

gmatnoob24
I keep getting (-1)^1 + (-1)^2 + (-1)^3 + (-1)^5 + (-1)^7 ... up til the 61st prime which is not equal to -1.

After (-1)^1 + (-1)^2 , you are left with the summation of -1's up to the 61st prime, what am I missing in this one MartyMurray?
Up till the 60th prime - so it would look like => \((-1)^1 + (-1)^2 + (-1)^3 + (-1)^4 + (-1)^5 + (-1)^6 + (-1)^7 ............ + (-1)^{280} + (-1)^{281}\), since 281 is the 60th prime.

We're not told that any integer n has to be a prime, it can be any integer up till the 60th prime => from integer 1 to the 60th prime.
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This makes sense now Krunaal, thank you! The key is if n is ANY INTEGER UP TIL THE 60TH PRIME. Which includes all even and odd integers. This indeed would make the answer -1. Appreciate your response.

Krunaal
hejwej
Am i misinterpreting what ADD means? is the question not asking us to: -1+1+(-1)+(-1)+(-1).....= ???

gmatnoob24
I keep getting (-1)^1 + (-1)^2 + (-1)^3 + (-1)^5 + (-1)^7 ... up til the 61st prime which is not equal to -1.

After (-1)^1 + (-1)^2 , you are left with the summation of -1's up to the 61st prime, what am I missing in this one MartyMurray?
Up till the 60th prime - so it would look like => \((-1)^1 + (-1)^2 + (-1)^3 + (-1)^4 + (-1)^5 + (-1)^6 + (-1)^7 ............ + (-1)^{280} + (-1)^{281}\), since 281 is the 60th prime.

We're not told that any integer n has to be a prime, it can be any integer up till the 60th prime => from integer 1 to the 60th prime.
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Krunaal
hejwej
Am i misinterpreting what ADD means? is the question not asking us to: -1+1+(-1)+(-1)+(-1).....= ???

gmatnoob24
I keep getting (-1)^1 + (-1)^2 + (-1)^3 + (-1)^5 + (-1)^7 ... up til the 61st prime which is not equal to -1.

After (-1)^1 + (-1)^2 , you are left with the summation of -1's up to the 61st prime, what am I missing in this one MartyMurray?
Up till the 60th prime - so it would look like => \((-1)^1 + (-1)^2 + (-1)^3 + (-1)^4 + (-1)^5 + (-1)^6 + (-1)^7 ............ + (-1)^{280} + (-1)^{281}\), since 281 is the 60th prime.

We're not told that any integer n has to be a prime, it can be any integer up till the 60th prime => from integer 1 to the 60th prime.
How do we find what the 60th prime number is? Is there a particular formula we can use or do we write down all prime numbers during the exam?
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Adidas1424

How do we find what the 60th prime number is? Is there a particular formula we can use or do we write down all prime numbers during the exam?

The actual value of the 60th prime doesn’t matter, and the GMAT doesn’t expect you to know it. What matters is that it’s definitely odd (since 2 is the only even prime), so the sequence ends with an odd exponent. That means you’re summing (-1)^1 + (-1)^2 + ... + (-1)^odd, which always ends with -1, giving a total sum of -1, regardless of the specific value of the 60th prime.
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Lets find out sum of the terms from 1 to 3rd prime number (which is 5)
hence n = 1, 2, 3, 4, 5
substituting values of n to find the sum
sum = -1 + 1 - 1 + 1 - 1 = -1

Lets now take sum of the terms from 1 to 4th prime number (which is 7)
hence n = 1, 2, 3, 4, 5, 6, 7
substituting values of n to find the sum
sum = -1 + 1 - 1 + 1 - 1 + 1 - 1 = -1

Therefore, we can conclude whatever be the value of the prime number involved, the sum of the terms is -1

IMO B

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MartyMurray
If \(a_n = (-1)^n\), what is the sum of all \(a_n\) if \(n\) is any integer from \(1\) to the \(60\)th prime number?

(A) -2

(B) -1

(C) 0

(D) 1

(E) 2
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what if n is 2? Wouldn't that still fit the criteria and answer = 0?
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joycechg
what if n is 2? Wouldn't that still fit the criteria and answer = 0?
n is any integer from 1 to 60th prime, and we want sum of all such \(a_n\) 's

i.e. \(a_1 + a_2 + a_3 + a_4 + ................... + a_{60th-prime-no.}\)
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Thanks! I was thinking if the prime integer = 2, then a1+a2 = (-1)^1+(-1)^2 = -1 + 1 = 0. Am I misinterpreting?

Krunaal
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joycechg
what if n is 2? Wouldn't that still fit the criteria and answer = 0?
n is any integer from 1 to 60th prime, and we want sum of all such \(a_n\) 's

i.e. \(a_1 + a_2 + a_3 + a_4 + ................... + a_{60th-prime-no.}\)
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joycechg
Am I misinterpreting?
Yes, \(n = 2\) is one possible value where \(a_2 = 1\). We have to take all the possible values from 1 to the 60th prime, and then find its sum.
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Yeah exactly.. seems some language issue with the question
hejwej
Am i misinterpreting what ADD means? is the question not asking us to: -1+1+(-1)+(-1)+(-1).....= ???
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