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04 Jun 2025, 00:30
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
54% (01:48) correct
46%
(01:57)
wrong
based on 164
sessions
History
Date
Time
Result
Not Attempted Yet
Find the number of ways in which 5 boys and 5 girls be seated in a row such that no two girls may sit together.
A. 35,400
B. 86,400
C. 28,800
D. 85,000
E. 25,000
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
A. 35,400
B. 86,400
C. 28,800
D. 85,000
E. 25,000
Gentle note to all experts and tutors: Please refrain from replying to this question until the Official Answer (OA) is revealed. Let students attempt to solve it first. You are all welcome to contribute posts after the OA is posted. Thank you all for your cooperation!
04 Jun 2025, 03:12
Kudos
Bookmarks
5 boys can be seated in 5! ways. The girls can be seated 6 positions in between boys and at the start or end.
_B_B_B_B_B_B_
Total ways = 5! * 6C5 * 5! = 120*120*6 = 86400
_B_B_B_B_B_B_
Total ways = 5! * 6C5 * 5! = 120*120*6 = 86400
Bunuel
04 Jun 2025, 08:19
Kudos
Bookmarks
5 boys can be seated in 5! ways
_B_B_B_B_B_
The 5 girls can take any 5 of the 6 _ seats and can be arranged in 5! ways.
Total arrangements= 6C5*5!*5!=6*120*120=86,400
Answer: B
_B_B_B_B_B_
The 5 girls can take any 5 of the 6 _ seats and can be arranged in 5! ways.
Total arrangements= 6C5*5!*5!=6*120*120=86,400
Answer: B
