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Bunuel
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Bunuel
Find the number of ways in which 5 boys and 5 girls be seated in a row such that no two girls may sit together.

A. 35,400
B. 86,400
C. 28,800
D. 85,000
E. 25,000


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No two girls sitting together. Let’s first place all boys equally spaced in a line.

_ B1_B2_B3_B4_B5_

The 6 blank spaces can be allocated for the five girls in 6 C 5 ways = 6 C1 = 6 ways.

The boys can be arranged in 5! Ways = 120

The girls allocated seats in 6 ways and can be arranged in 5! Ways = 6* 5!

Number of ways = 120 * 6*5! = 120*720 = 86400

Option B
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Not much to add here, but for these kind of questions you can often use divisibility to shortcut the maths at the end or double check your answers

6*5!*5! will have a 3x3 = 9 in it so the answer will be divisible by 9

By adding the digits of the answer choices and checking if the sum is divisible by 9, we can see that only B and C are divisible by 9.

When under time pressure (which happens a lot in the GMAT!) you can use these little tricks to make guesses when short on time or double check your answers
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