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John, Steve, and Mary are buying a car with a list price of $24,000. John contributes three times as much as Steve, who contributes half as much as Mary. At the dealership, the trio buys the car and receives a 15% rebate. If they split the rebate funds proportional to each person's initial investment, how much more money does John receive back compared to Mary?

A. $400
B. $600
C. $1,200
D. $1,800
E. $3,600

Source: Veritas Prep

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Let the contribution by John, Steve and Mary be J, S , M respectively.

J + S + M = $ 24,000

J = 3S

M = 2S

Hence, the equation becomes 3S+ S + 2S = 24000

6S = 24000

S = 4000

J:S:M = 3S : S : 2S = 3:1:2 ( the ratio of their investments).

They receive 15% rebate = 15%*(24000) = $3600.

J:S:M = 3S : S : 2S = 3x:1x:2x = 6x = $3600

x = $600.

John more than Mary is 3x -2x = x = $600

Option B
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J+M+S= 24,000
J=3S and M=2S; J=(3/2)M
(3/2)M+M+(1/2)M=24,000
M=8,000
S=4,000
J=12,000
J:M:S=3:2:1
Rebate= 24,000*15%= 3600
J gets back = 3*600
And M gets back= 2*600
Difference= 1800-1200= 600

Answer: B
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Express each person’s contribution in terms of Steve’s contribution.
\(\text{Let's call Steve's contribution} = S\)
\(\text{Then John’s contribution} = 3S\)
\(\text{And Mary’s contribution} = 2S\)

Determine the total combined contribution in terms of S.
\(\text{Total contribution} = S + 3S + 2S = 6S\)

Now we can calculate the total rebate amount as 15% of the car’s list price.
\(\text{Total rebate} = 24000 \times 0.15 = 3600\)

and find John’s share of the rebate proportional to his contribution.
\(\text{John’s share} = 3600 \times \frac{3S}{6S} = 3600 \times \frac{1}{2} = 1800\)

Now we can find Mary’s share of the rebate proportional to her contribution.
\(\text{Mary’s share} = 3600 \times \frac{2S}{6S} = 3600 \times \frac{1}{3} = 1200\)

Calculate how much more John receives compared to Mary.
\(1800 - 1200 = 600\)

Answer 600 (B)

Hope this helps!
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