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Is there any short method to solve this apart from using substitution?
Bunuel
In a Chemistry lab, there are three solutions of an acid – A, B and C – of concentrations 45%, 50% and c% respectively. If 100 ml of A when mixed with V ml of C, produces a solution of 60% concentration and 100 ml of B when mixed with V ml of C, produces a solution of 62% concentration, what is the value of V?

A. 80
B. 100
C. 120
D. 150
E. 175


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okHedwig
Is there any short method to solve this apart from using substitution?

okHedwig

Yes, there's a powerful shortcut using the "Weighted Average Difference" technique!

Here's the clever approach that avoids substitution entirely:

Key Insight:
When the same volumes are mixed (\(100\) ml and \(V\) ml in both cases), the difference in final concentrations tells us about the relationship between solutions.

The Shortcut Method:

Step 1: Set up the concentration differences
- Mixture 1: \(100\) ml of \(45\%\) + \(V\) ml of \(c\%\) = \(60\%\)
- Mixture 2: \(100\) ml of \(50\%\) + \(V\) ml of \(c\%\) = \(62\%\)

Step 2: Find the impact of changing from A to B
When we switch from solution A (\(45\%\)) to solution B (\(50\%\)):
- The \(100\) ml portion increases by \(5\%\) (from \(45\%\) to \(50\%\))
- The final concentration increases by \(2\%\) (from \(60\%\) to \(62\%\))

Step 3: Calculate the volume ratio
The \(5\%\) increase in \(100\) ml causes a \(2\%\) increase in the total mixture.
This means: \(\frac{100}{100 + V} = \frac{2}{5}\)

Solving: \(500 = 200 + 2V\)
Therefore: \(V = 150\)

Why This Works:
The weighted average principle tells us that the impact of changing one component is proportional to its weight in the mixture. When \(100\) ml represents \(\frac{2}{5}\) of the total mixture, we can directly calculate \(V\).

Time-Saving Tip for GMAT:
Whenever you see two mixtures with:
- Same volumes being mixed
- Different concentrations of one component
- Different final results

Think "weighted average difference" instead of setting up two equations!

Practice Recognition Pattern:
Look for problems where:
  1. Two similar mixtures are created
  2. Only one component changes between them
  3. You need to find the unknown volume or concentration

This technique can save you 1-2 minutes on similar GMAT problems - time you can use elsewhere!

You can practice similar mixture and weighted average problems here - focus on concentration and ratio questions to master these shortcut techniques. This free trial covers systematic approaches to time-saving methods and pattern recognition for various Quant concepts.
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