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Bunuel
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Bob buys some candies for $15 a dozen and an equal number of different 23 Sep 2025, 02:02
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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75% (hard)

Question Stats:

58% (02:21) correct 42% (02:31) wrong based on 84 sessions

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Bob buys some candies for $15 a dozen and an equal number of different candies for $12 a dozen. He sells all for $16.50 a dozen and makes a profit of $150. How many dozens of candies did he buy altogether?

(A) 50
(B) 45
(C) 40
(D) 30
(E) 25


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Ghuhan
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Bob buys some candies for $15 a dozen and an equal number of different 23 Sep 2025, 10:58
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x = dozen

15x + 12x = T (TOTAL)
(16.5)2x = T + 150

integrate both equation

(15 + 12 - 33 )x = -150

-6x=-150

x=25

HOPE ITS RIGHT !!!
Im new to gmat club started out studying for my 1st gmat exam
Im sorry if its wrong
Thank you !!!!
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Bob buys some candies for $15 a dozen and an equal number of different 23 Sep 2025, 11:43
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Hi,

It should be 50 as he buys 2 different candies and each at the same amount. So 25+25 = 50.
Ghuhan
x = dozen

15x + 12x = T (TOTAL)
(16.5)2x = T + 150

integrate both equation

(15 + 12 - 33 )x = -150

-6x=-150

x=25

HOPE ITS RIGHT !!!
Im new to gmat club started out studying for my 1st gmat exam
Im sorry if its wrong
Thank you !!!!
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Bob buys some candies for $15 a dozen and an equal number of different 23 Sep 2025, 18:41
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cp 1 15$
CP2 12$

Sp 16.5$

Profit from 1st set / dozen is 1.5$
Profit from 2nd set/dozen is 4.5$

Total profit 6$

He made a total profit of 150$
150/6=25
So he must buy 25 dozen of each set to fulfil this condition. Hence Option A should be the answer
Bunuel
Bob buys some candies for $15 a dozen and an equal number of different candies for $12 a dozen. He sells all for $16.50 a dozen and makes a profit of $150. How many dozens of candies did he buy altogether?

(A) 50
(B) 45
(C) 40
(D) 30
(E) 25


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Bob buys some candies for $15 a dozen and an equal number of different 23 Sep 2025, 19:12
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Bunuel
Bob buys some candies for $15 a dozen and an equal number of different candies for $12 a dozen. He sells all for $16.50 a dozen and makes a profit of $150. How many dozens of candies did he buy altogether?

(A) 50
(B) 45
(C) 40
(D) 30
(E) 25


­
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Let the number of dozen candies Bob buys for $15 and $12 are a and b respectively.

Given that a=b (equal number of candies).

Cost price = 15a + 12b = 27a

Selling price = 16.50 (a+b) = 16.50*(2a) = 33a

Profit = 33a - 27a = 6a

Moreover, Profit = 6a = $150

a = 150/6 = 25.

If a = 25, then b = 25.

Hence, the total number of dozens bought = 25+25 =50.

Option A
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Bob buys some candies for $15 a dozen and an equal number of different 23 Sep 2025, 20:39
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number of dozens of each type of candy Bob buys = n
Total cost of candies of both type = 15n+12n=27n
SP= 16.5n*2=33n
Profit= SP-CP= 33n-27n=150
6n=150 ; n=150/6=25

Bob buys n dozen of both type of candies. So, total dozens of candies bought = n+n=2n =2*25=50

A
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