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26 Jan 2026, 06:22
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
47% (03:17) correct
53%
(03:39)
wrong
based on 34
sessions
History
Date
Time
Result
Not Attempted Yet
On a typical day, Jimmy leaves home at 5:00 PM, drives at a constant 35 mph to his wife's office, picks her up at 6:00 PM, and they reach home at 7:00 PM. One Friday, the office closed at 5:00 PM, and his wife immediately started biking toward home at a constant speed. Jimmy left at 5:00 PM as usual, met her en route, and they arrived home 15 minutes earlier than usual. What was her cycling speed?
A. 4 mph
B. 5 mph
C. 5.5 mph
D. 6 mph
E. 6.5 mph
A. 4 mph
B. 5 mph
C. 5.5 mph
D. 6 mph
E. 6.5 mph
26 Jan 2026, 08:52
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Usual Schedule
Jimmy drives to the office at 35 mph, arriving at 6:00 PM (1 hour), a distance of 35 miles. They drive back home in 1 hour, arriving at 7:00 PM (total 2 hours from 5:00 PM).
Friday Scenario
His wife bikes toward home from 5:00 PM at b mph. Jimmy drives toward the office at 35 mph from 5:00 PM. They meet after t hours where 35t+bt=35,
so, t = \(\frac{35 }{ 35 + b}\).
Return Trip
Meeting point is 35t miles from home. Driving back at 35 mph takes t hours. Total time: 2t hours, which is 1.75 hours (15 minutes early).
Speed Calculation
2t=1.75, so, t=0.875 hours.
Then
0.875 = \(\frac{35 }{ 35 + b}\),
35+b=40,
b=5 mph.
ANS = B
Jimmy drives to the office at 35 mph, arriving at 6:00 PM (1 hour), a distance of 35 miles. They drive back home in 1 hour, arriving at 7:00 PM (total 2 hours from 5:00 PM).
Friday Scenario
His wife bikes toward home from 5:00 PM at b mph. Jimmy drives toward the office at 35 mph from 5:00 PM. They meet after t hours where 35t+bt=35,
so, t = \(\frac{35 }{ 35 + b}\).
Return Trip
Meeting point is 35t miles from home. Driving back at 35 mph takes t hours. Total time: 2t hours, which is 1.75 hours (15 minutes early).
Speed Calculation
2t=1.75, so, t=0.875 hours.
Then
0.875 = \(\frac{35 }{ 35 + b}\),
35+b=40,
b=5 mph.
ANS = B
