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03 Feb 2026, 06:32
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
83% (03:07) correct
17%
(04:01)
wrong
based on 23
sessions
History
Date
Time
Result
Not Attempted Yet
A and B together can do a piece of work in 40 days. After working for 10 days, they get assistance from C and the work is finished in another 20 days. If C does as much work in 2 days as B does in 3 days, in how many days can A, B and C do the same work alone, respectively?
A. 50, 100, 70
B. 60, 110, 75
C. 70, 120, 90
D. 60, 120, 80
E. 50, 90, 70
(Source=TCYOnline)
A. 50, 100, 70
B. 60, 110, 75
C. 70, 120, 90
D. 60, 120, 80
E. 50, 90, 70
(Source=TCYOnline)
03 Feb 2026, 06:33
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Right Answer Explanation / Suggested Answer :
Let the work done by A in one day be A, that by B be B, and that by C be C.
Let the total work be W.
As A and B together can do the work in 40 days, we have
40(A + B) = W
Or A + B = ... (i)
Now, work done by A and B in 10 days = 10(A + B) ... (ii)
Plugging in the value of A + B from equation (i) in terms of W into equation (ii), we get
Work done by A and B in 10 days = 10(A + B) = =
Work left to be done =
This work is done by A, B and C in 20 days.
Work done by A, B and C in 20 days = 20(A + B + C) = ... (iii)
Now, work done by C in 2 days = work done by B in 3 days
So, 2C = 3B
Or C = B ... (iv)
Now, plugging in the value of A as - B from equation (i) and the value of C as B from equation (iv) into equation (iii), we get
120B = W
Or B = ... (v)
So, A =
Let the number of days taken by A to do the work alone be 'd'.
So, dA = W
Or = W
Or d = 60
Let the number of days taken by B to do the work be 'f'.
So, fB = W
Or = W
Or f = 120
As C takes 2 days to do the work that B does in 3 days, C takes = 80 days to do the same work.
Thus, A, B and C respectively take 60, 120 and 80 days to do the work alone.
Thus, answer option 4 is correct.
Let the work done by A in one day be A, that by B be B, and that by C be C.
Let the total work be W.
As A and B together can do the work in 40 days, we have
40(A + B) = W
Or A + B = ... (i)
Now, work done by A and B in 10 days = 10(A + B) ... (ii)
Plugging in the value of A + B from equation (i) in terms of W into equation (ii), we get
Work done by A and B in 10 days = 10(A + B) = =
Work left to be done =
This work is done by A, B and C in 20 days.
Work done by A, B and C in 20 days = 20(A + B + C) = ... (iii)
Now, work done by C in 2 days = work done by B in 3 days
So, 2C = 3B
Or C = B ... (iv)
Now, plugging in the value of A as - B from equation (i) and the value of C as B from equation (iv) into equation (iii), we get
120B = W
Or B = ... (v)
So, A =
Let the number of days taken by A to do the work alone be 'd'.
So, dA = W
Or = W
Or d = 60
Let the number of days taken by B to do the work be 'f'.
So, fB = W
Or = W
Or f = 120
As C takes 2 days to do the work that B does in 3 days, C takes = 80 days to do the same work.
Thus, A, B and C respectively take 60, 120 and 80 days to do the work alone.
Thus, answer option 4 is correct.
Amity007
