In an event, only candidates and recruiters participate.

Question

In an event, only candidates and recruiters participate. Candidates can meet the recruiters for one-on-one information sessions. One candidate can have such a session with the only recruiter in a day; one recruiter meets only one candidate per day for such a session. During the first day of the event, 10% of the candidates in the event and 50% of the recruiters in the event participated in one-on-one information sessions. What percentage of the total individuals attending the event participated in one-on-one information sessions during the first day of the event?

A. 10%
B. 16.67%
C. 20%
D. 30%
E. 33.33%

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A. 10%
B. 16.67%
C. 20%
D. 30%
E. 33.33%

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Dereno · Answer

Given that,

1 candidate meets for a session with 1 Recruiter, per day.

10% Candidates = 50% of Recruiters

Ratio of Candidates : Recruiters = 5:1

So let’s assume the total number of individuals to be 60.

Candidates = 50

Recruiters = 10.

10%*(candidates) = 10%*50 = 5

While 50%*(Recruiters) = 50%*(10) = 5

Total participants on day 1 = 10.

% of participants on day 1 wrt Total = 10/60

=  16.66%

Option B

temporibusullam · Answer

I disagree. If one recruiter meets one candidate per day and vice versa, assuming there are 50 candidates (10% of 500 candidates) and there are 50 recruiters (50% of 100 recruiters), then the total % of individuals met in the first day of the event will be

(50+50)/600x100 = 10%

(50+50)/600x100 = 10%

Adit_ · Answer

Umm..you did everything right except the calculation in the end. Your calculation right up till the end is perfect, the value is not 10% its 16.67%. Kindly check.

Edskore · Answer

The concept being tested here is weighted percentage with a hidden ratio constraint — the kind that looks like a straightforward percentage problem until you realise the two groups are not independent.

The key insight most people miss: the problem doesn't tell you how many candidates or recruiters there are. You have to let the constraint pin down the ratio between them.

Step 1 — Set up variables.
Let C = number of candidates, R = number of recruiters. Total people = C + R.

Step 2 — Use the session constraint to relate C and R.
"One candidate can have a session with only one recruiter per day; one recruiter meets only one candidate per day." This means the number of sessions = number of participating candidates = number of participating recruiters.

So: 10% of C = 50% of R
→ 0.10C = 0.50R → C = 5R

Step 3 — Count total session participants.
Candidates in sessions + Recruiters in sessions
= 0.10C + 0.50R
= 0.10(5R) + 0.50R
= 0.50R + 0.50R = R

Step 4 — Express as a percentage of everyone.
Total people = C + R = 5R + R = 6R
% who participated = R / 6R = 1/6 ≈ 16.67% → Answer: B

Common trap: The mistake in an earlier reply was assuming C = 500 and R = 100 freely, then computing (50+50)/600 = 10%. That setup actually does satisfy C = 5R correctly — but the arithmetic went wrong at the end. 100 total session participants out of 600 total people = 100/600 = 16.67%, not 10%. The numerator should be R (100), not 50+50 recounted as if they're different people.

Takeaway: Any time a problem says "X% of group A = Y% of group B," write it as an equation immediately — it locks in the ratio between the groups and everything else follows cleanly.

ExpertsGlobal5 · Answer

Video explanation:

https://www.youtube.com/watch?v=Qex5_WmMnt8

In an event, only candidates and recruiters participate.

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In an event, only candidates and recruiters participate.

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