Step 1: Set up variablesLet
x = % of residents in NONE of the activities
Then: residents in ALL THREE =
x/2 (given)
Step 2: Use what "two or more" means"Two or more" = (exactly 2) + (all 3) =
65%So: (exactly 2) = 65 - x/2
Step 3: Find "only one"All regions must add to
100%:
(only one) + (exactly 2) + (all 3) + (none) = 100
(only one) + (65 - x/2) + (x/2) + x = 100
(only one) =
35 - xStep 4: Apply the key formulaSum of individual sets = (only one) + 2(exactly two) + 3(all three)Why this formula works: When you add up 40% + 50% + 60%, people in exactly 2 activities get counted twice, and people in all 3 get counted three times. This formula accounts for that.
Plugging in:
40 + 50 + 60 = (35 - x) + 2(65 - x/2) + 3(x/2)
150 = 35 - x + 130 - x + 3x/2
150 = 165 - x/2
x/2 = 15x = 30Answer: E (30%)In 3-set Venn problems, think in terms of 4 regions: (only one), (exactly two), (all three), and (none). They always sum to 100%, and this often gives you the equation you need.monker1231
Lets say 100 residents in the community:
No activity: N residents
1 Activity : O residents
2 Activities: T residents
3 Activities: TR residents
Now we know:
N + O + T + TR = 100
T + TR = 65
2TR = N
Additionally we know:
O + 2T +3TR = 40 + 50 + 60 = 150
Now we subtract the formulas to get a result:
O + 2T + 3TR = 150
(-) N + O + T + TR = 100
=> -N + T + 2TR = 50
Now we substitute T with = 65-TR
and substitute N with = 2TR
=> -2TR + (65 - TR) + 2TR = 50
=> Solved for TR = 15
N = 2TR so 2*15 = 30
Result is E (30)
Are there quicker ways to solve it? Please give Kudos if this helped
