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Would it matter if it were stated?
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total people= 50
each ordered exactly one drink
wine = 6$, beer= 5$ and water= 1$
total cost = 199

say people with wine = x
people with beer = y
people with water =z

x+y+z = 50

6x+5y + z = 199

we need maximum people with wine. so lets minimize the other two.
x = 50-y- z

put into second equ,

6(50-y-z) + 5y + z = 199
300-6y-6z +5y+z = 199
101 = y+ 5z
z is multiple of 5 so with that in mind lets try value for y and then find for z.
y=1 , z=20 so x= 29
y=6, z= 19 so x= 25
y=11 , z= 18, so x= 21

x is decreasing with each rep. that means the greatest value for x can be 29

option B
kevincan
A bus carrying 50 tourists stopped at a roadside restaurant. Each tourist ordered exactly one beverage: wine for €6, beer for €5, or water for €1. If the group’s total bill was €199, what is the greatest possible number of tourists who ordered wine?

(A) 28
(B) 29
(C) 30
(D) 31
(E) 33
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if they mentioned atleast one of each was ordered, one wouldn't have put 0 for Beer, hence making 33 wines and 1 water bottle amounting to 199
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Remember that each tourist ordered exactly one beverage , so even though 33 tourists ordering wine and 1 ordering water would result in a total of 199, there would be 16 tourists with nothing to drink
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If numbe of people who drink beer is zero, it would not satisfy the first equation of x+y+z=50.

Hope it helps!

Thanks,
3434will
You didn't say at least one of each was ordered.
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