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Would it matter if it were stated?
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total people= 50
each ordered exactly one drink
wine = 6$, beer= 5$ and water= 1$
total cost = 199

say people with wine = x
people with beer = y
people with water =z

x+y+z = 50

6x+5y + z = 199

we need maximum people with wine. so lets minimize the other two.
x = 50-y- z

put into second equ,

6(50-y-z) + 5y + z = 199
300-6y-6z +5y+z = 199
101 = y+ 5z
z is multiple of 5 so with that in mind lets try value for y and then find for z.
y=1 , z=20 so x= 29
y=6, z= 19 so x= 25
y=11 , z= 18, so x= 21

x is decreasing with each rep. that means the greatest value for x can be 29

option B
kevincan
A bus carrying 50 tourists stopped at a roadside restaurant. Each tourist ordered exactly one beverage: wine for €6, beer for €5, or water for €1. If the group’s total bill was €199, what is the greatest possible number of tourists who ordered wine?

(A) 28
(B) 29
(C) 30
(D) 31
(E) 33
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