To determine which of the statements are true, let's analyze each one using the definition of the operation a∗b=a+b−ab:
Statement I: a∗b=b∗aLet's find the expression for both sides:
- Left-hand side (LHS): a∗b=a+b−ab
- Right-hand side (RHS): b∗a=b+a−ba
Since addition and multiplication are commutative for integers (a+b=b+a and ab=ba), the expression b+a−ba is equivalent to a+b−ab. Thus, a∗b=b∗a.
Statement I is true.Statement II: a∗0=aSubstitute b=0 into the definition:
a∗0=a+0−a(0)
a∗0=a+0−0=a
Thus, a∗0=a.
Statement II is true.Statement III: (a∗b)∗c=a∗(b∗c)Let's expand both sides to check for associativity:
- Left-hand side (LHS):
(a∗b)∗c=(a+b−ab)∗c
Applying the operation again, treating (a+b−ab) as the first term and c as the second term:
=(a+b−ab)+c−(a+b−ab)c
=a+b−ab+c−ac−bc+abc
=a+b+c−ab−ac−bc+abc - Right-hand side (RHS):
a∗(b∗c)=a∗(b+c−bc)
Applying the operation again, treating a as the first term and (b+c−bc) as the second term:
=a+(b+c−bc)−a(b+c−bc)
=a+b+c−bc−ab−ac+abc
=a+b+c−ab−ac−bc+abc
Since the LHS expression simplifies to the exact same polynomial as the RHS expression, the operation is associative. Thus, (a∗b)∗c=a∗(b∗c).
Statement III is true.Since all three statements (I, II, and III) are true, the correct choice is
E.
Correct Answer: E. I, II and IIIarchitkap
If the operation * is defined for all integers a and b by a*b = a+b-ab, which of the following statements could be true?
I. a*b=b*a
II. a*0=a
III. (a*b)*c = a*(b*c)
A. I
B. II
C. I and II
D. II and III
E. I, II and III